Solve 2 (x-1) 3 (7x) -10 = 34

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

x_{1} = \frac{21 - 2289}{42}, x_{2} = \frac{21 + 2289}{42}

Alternative Form

x_{1} \approx - 0.639131, x_{2} \approx 1.639131

Evaluate

2 (x - 1) \times 3 \times 7 x - 10 = 34

Multiply

More Steps

42 x (x - 1) - 10 = 34

Expand the expression

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42 x^{2} - 42 x - 10 = 34

Move the expression to the left side

42 x^{2} - 42 x - 44 = 0

Substitute a= 42,b= - 42 and c= - 44 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{42 \pm ( - 42 ) ^{2} - 4 \times 42 ( - 44 )}{2 \times 42}

Simplify the expression

x = \frac{42 \pm ( - 42 ) ^{2} - 4 \times 42 ( - 44 )}{84}

Simplify the expression

More Steps

x = \frac{42 \pm 9156}{84}

Simplify the radical expression

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x = \frac{42 \pm 2 2289}{84}

Separate the equation into 2 possible cases

x = \frac{42 + 2 2289}{84} x = \frac{42 - 2 2289}{84}

Simplify the expression

More Steps

x = \frac{21 + 2289}{42} x = \frac{42 - 2 2289}{84}

Simplify the expression

More Steps

x = \frac{21 + 2289}{42} x = \frac{21 - 2289}{42}

Solution

x_{1} = \frac{21 - 2289}{42}, x_{2} = \frac{21 + 2289}{42}

Alternative Form

x_{1} \approx - 0.639131, x_{2} \approx 1.639131

Show Solution