Question
Solve the equation
t1=−315,t2=315
Alternative Form
t1≈−1.290994,t2≈1.290994
Evaluate
3t2×22=51
Find the domain
More Steps

Evaluate
3t2×2=0
Multiply the terms
6t2=0
Rewrite the expression
t2=0
The only way a power can not be 0 is when the base not equals 0
t=0
3t2×22=51,t=0
Reduce the fraction
More Steps

Evaluate
3t2×22
Multiply the terms
6t22
Reduce the fraction
3t21
3t21=51
Rewrite the expression
3t2=5
Divide both sides
33t2=35
Divide the numbers
t2=35
Take the root of both sides of the equation and remember to use both positive and negative roots
t=±35
Simplify the expression
More Steps

Evaluate
35
To take a root of a fraction,take the root of the numerator and denominator separately
35
Multiply by the Conjugate
3×35×3
Multiply the numbers
More Steps

Evaluate
5×3
The product of roots with the same index is equal to the root of the product
5×3
Calculate the product
15
3×315
When a square root of an expression is multiplied by itself,the result is that expression
315
t=±315
Separate the equation into 2 possible cases
t=315t=−315
Check if the solution is in the defined range
t=315t=−315,t=0
Find the intersection of the solution and the defined range
t=315t=−315
Solution
t1=−315,t2=315
Alternative Form
t1≈−1.290994,t2≈1.290994
Show Solution
