Solve 2(x-11)^2-(x-3)(x 1) 5

Question

Simplify the expression

- 3 x^{2} - 29 x + 242

Show Solution

x_{1} = - \frac{29 + 3745}{6}, x_{2} = \frac{- 29 + 3745}{6}

Alternative Form

x_{1} \approx - 15.032734, x_{2} \approx 5.366068

Evaluate

2 (x - 11)^{2} - (x - 3) (x \times 1) \times 5

To find the roots of the expression,set the expression equal to 0

2 (x - 11)^{2} - (x - 3) (x \times 1) \times 5 = 0

Any expression multiplied by 1 remains the same

2 (x - 11)^{2} - (x - 3) x \times 5 = 0

Multiply the terms

More Steps

2 (x - 11)^{2} - 5 x (x - 3) = 0

Calculate

More Steps

- 3 x^{2} - 29 x + 242 = 0

Multiply both sides

3 x^{2} + 29 x - 242 = 0

Substitute a= 3,b= 29 and c= - 242 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{- 29 \pm 2 9 ^{2} - 4 \times 3 ( - 242 )}{2 \times 3}

Simplify the expression

x = \frac{- 29 \pm 2 9 ^{2} - 4 \times 3 ( - 242 )}{6}

Simplify the expression

More Steps

x = \frac{- 29 \pm 3745}{6}

Separate the equation into 2 possible cases

x = \frac{- 29 + 3745}{6} x = \frac{- 29 - 3745}{6}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

x = \frac{- 29 + 3745}{6} x = - \frac{29 + 3745}{6}

Solution

x_{1} = - \frac{29 + 3745}{6}, x_{2} = \frac{- 29 + 3745}{6}

Alternative Form

x_{1} \approx - 15.032734, x_{2} \approx 5.366068

Show Solution