Solve 20+(6x^2) - ScanMath

Question

Factor the expression

2 (10 + 3 x^{2})

Evaluate

20 + 6 x^{2}

Solution

2 (10 + 3 x^{2})

Show Solution

x_{1} = - \frac{30}{3} i, x_{2} = \frac{30}{3} i

Alternative Form

x_{1} \approx - 1.825742 i, x_{2} \approx 1.825742 i

Evaluate

20 + (6 x^{2})

To find the roots of the expression,set the expression equal to 0

20 + (6 x^{2}) = 0

Multiply the terms

20 + 6 x^{2} = 0

Move the constant to the right-hand side and change its sign

6 x^{2} = 0 - 20

Removing 0 doesn't change the value,so remove it from the expression

6 x^{2} = - 20

Divide both sides

\frac{6 x ^{2}}{6} = \frac{- 20}{6}

Divide the numbers

x^{2} = \frac{- 20}{6}

Divide the numbers

More Steps

Evaluate

\frac{- 20}{6}

Cancel out the common factor 2

\frac{- 10}{3}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

- \frac{10}{3}

x^{2} = - \frac{10}{3}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm - \frac{10}{3}

Simplify the expression

More Steps

Evaluate

- \frac{10}{3}

Evaluate the power

\frac{10}{3} \times - 1

Evaluate the power

\frac{10}{3} \times i

Evaluate the power

More Steps

Evaluate

\frac{10}{3}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{10}{3}

Multiply by the Conjugate

\frac{10 \times 3}{3 \times 3}

Multiply the numbers

\frac{30}{3 \times 3}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{30}{3}

\frac{30}{3} i

x = \pm \frac{30}{3} i

Separate the equation into 2 possible cases

x = \frac{30}{3} i x = - \frac{30}{3} i

Solution

x_{1} = - \frac{30}{3} i, x_{2} = \frac{30}{3} i

Alternative Form

x_{1} \approx - 1.825742 i, x_{2} \approx 1.825742 i

Show Solution