Solve 20y^2 - 160y - 165

Question

Factor the expression

5 (4 y^{2} - 32 y - 33)

Show Solution

y_{1} = \frac{8 - 97}{2}, y_{2} = \frac{8 + 97}{2}

Alternative Form

y_{1} \approx - 0.924429, y_{2} \approx 8.924429

Evaluate

20 y^{2} - 160 y - 165

To find the roots of the expression,set the expression equal to 0

20 y^{2} - 160 y - 165 = 0

Substitute a= 20,b= - 160 and c= - 165 into the quadratic formula y = \frac{- b \pm b ^{2} - 4 a c}{2 a}

y = \frac{160 \pm ( - 160 ) ^{2} - 4 \times 20 ( - 165 )}{2 \times 20}

Simplify the expression

y = \frac{160 \pm ( - 160 ) ^{2} - 4 \times 20 ( - 165 )}{40}

Simplify the expression

More Steps

y = \frac{160 \pm 38800}{40}

Simplify the radical expression

More Steps

y = \frac{160 \pm 20 97}{40}

Separate the equation into 2 possible cases

y = \frac{160 + 20 97}{40} y = \frac{160 - 20 97}{40}

Simplify the expression

More Steps

y = \frac{8 + 97}{2} y = \frac{160 - 20 97}{40}

Simplify the expression

More Steps

y = \frac{8 + 97}{2} y = \frac{8 - 97}{2}

Solution

y_{1} = \frac{8 - 97}{2}, y_{2} = \frac{8 + 97}{2}

Alternative Form

y_{1} \approx - 0.924429, y_{2} \approx 8.924429

Show Solution