Solve 2199-12-31t^23:59:59

Evaluate

2199 - 12 - 31 t^{2} \times 3 \div 59 \div 59

To find the roots of the expression,set the expression equal to 0

2199 - 12 - 31 t^{2} \times 3 \div 59 \div 59 = 0

Multiply the terms

2199 - 12 - 93 t^{2} \div 59 \div 59 = 0

Rewrite the expression

2199 - 12 - \frac{93 t ^{2}}{59} \div 59 = 0

Divide the terms

More Steps

2199 - 12 - \frac{93 t ^{2}}{3481} = 0

Subtract the numbers

2187 - \frac{93 t ^{2}}{3481} = 0

Subtract the terms

More Steps

\frac{7612947 - 93 t ^{2}}{3481} = 0

Simplify

7612947 - 93 t^{2} = 0

Rewrite the expression

- 93 t^{2} = - 7612947

Change the signs on both sides of the equation

93 t^{2} = 7612947

Divide both sides

\frac{93 t ^{2}}{93} = \frac{7612947}{93}

Divide the numbers

t^{2} = \frac{7612947}{93}

Cancel out the common factor 3

t^{2} = \frac{2537649}{31}

Take the root of both sides of the equation and remember to use both positive and negative roots

t = \pm \frac{2537649}{31}

Simplify the expression

More Steps

t = \pm \frac{1593 31}{31}

Separate the equation into 2 possible cases

t = \frac{1593 31}{31} t = - \frac{1593 31}{31}

Solution

t_{1} = - \frac{1593 31}{31}, t_{2} = \frac{1593 31}{31}

Alternative Form

t_{1} \approx - 286.111246, t_{2} \approx 286.111246

Simplify the expression