Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
(3q+1)(7q+1)
Evaluate
21q2+10q+1
Rewrite the expression
21q2+(3+7)q+1
Calculate
21q2+3q+7q+1
Rewrite the expression
3q×7q+3q+7q+1
Factor out 3q from the expression
3q(7q+1)+7q+1
Solution
(3q+1)(7q+1)
Show Solution
Find the roots
q1=−31,q2=−71
Alternative Form
q1=−0.3˙,q2=−0.1˙42857˙
Evaluate
21q2+10q+1
To find the roots of the expression,set the expression equal to 0
21q2+10q+1=0
Factor the expression
More Steps
Evaluate
21q2+10q+1
Rewrite the expression
21q2+(3+7)q+1
Calculate
21q2+3q+7q+1
Rewrite the expression
3q×7q+3q+7q+1
Factor out 3q from the expression
3q(7q+1)+7q+1
Factor out 7q+1 from the expression
(3q+1)(7q+1)
(3q+1)(7q+1)=0
When the product of factors equals 0,at least one factor is 0
3q+1=07q+1=0
Solve the equation for q
More Steps
Evaluate
3q+1=0
Move the constant to the right-hand side and change its sign
3q=0−1
Removing 0 doesn't change the value,so remove it from the expression
3q=−1
Divide both sides
33q=3−1
Divide the numbers
q=3−1
Use b−a=−ba=−ba to rewrite the fraction
q=−31
q=−317q+1=0
Solve the equation for q
More Steps
Evaluate
7q+1=0
Move the constant to the right-hand side and change its sign
7q=0−1
Removing 0 doesn't change the value,so remove it from the expression
7q=−1
Divide both sides
77q=7−1
Divide the numbers
q=7−1
Use b−a=−ba=−ba to rewrite the fraction
q=−71
q=−31q=−71
Solution
q1=−31,q2=−71
Alternative Form
q1=−0.3˙,q2=−0.1˙42857˙
Show Solution