Solve 23-26m^2 - ScanMath

Question

Find the roots

m_{1} = - \frac{598}{26}, m_{2} = \frac{598}{26}

Alternative Form

m_{1} \approx - 0.94054, m_{2} \approx 0.94054

Evaluate

23 - 26 m^{2}

To find the roots of the expression,set the expression equal to 0

23 - 26 m^{2} = 0

Move the constant to the right-hand side and change its sign

- 26 m^{2} = 0 - 23

Removing 0 doesn't change the value,so remove it from the expression

- 26 m^{2} = - 23

Change the signs on both sides of the equation

26 m^{2} = 23

Divide both sides

\frac{26 m ^{2}}{26} = \frac{23}{26}

Divide the numbers

m^{2} = \frac{23}{26}

Take the root of both sides of the equation and remember to use both positive and negative roots

m = \pm \frac{23}{26}

Simplify the expression

More Steps

Evaluate

\frac{23}{26}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{23}{26}

Multiply by the Conjugate

\frac{23 \times 26}{26 \times 26}

Multiply the numbers

More Steps

Evaluate

23 \times 26

The product of roots with the same index is equal to the root of the product

23 \times 26

Calculate the product

598

\frac{598}{26 \times 26}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{598}{26}

m = \pm \frac{598}{26}

Separate the equation into 2 possible cases

m = \frac{598}{26} m = - \frac{598}{26}

Solution

m_{1} = - \frac{598}{26}, m_{2} = \frac{598}{26}

Alternative Form

m_{1} \approx - 0.94054, m_{2} \approx 0.94054

Show Solution