Solve 2482/\beta /5-12-2008

Evaluate

\frac{2482}{β} \div 5 - 12 - 2008

To find the roots of the expression,set the expression equal to 0

\frac{2482}{β} \div 5 - 12 - 2008 = 0

Find the domain

\frac{2482}{β} \div 5 - 12 - 2008 = 0, β \neq = 0

Calculate

\frac{2482}{β} \div 5 - 12 - 2008 = 0

Divide the terms

More Steps

\frac{2482}{5 β} - 12 - 2008 = 0

Subtract the terms

More Steps

\frac{2482 - 60 β}{5 β} - 2008 = 0

Subtract the terms

More Steps

\frac{2482 - 10100 β}{5 β} = 0

Cross multiply

2482 - 10100 β = 5 β \times 0

Simplify the equation

2482 - 10100 β = 0

Move the constant to the right side

- 10100 β = 0 - 2482

Removing 0 doesn't change the value,so remove it from the expression

- 10100 β = - 2482

Change the signs on both sides of the equation

10100 β = 2482

Divide both sides

\frac{10100 β}{10100} = \frac{2482}{10100}

Divide the numbers

β = \frac{2482}{10100}

Cancel out the common factor 2

β = \frac{1241}{5050}

Check if the solution is in the defined range

β = \frac{1241}{5050}, β \neq = 0

Solution

β = \frac{1241}{5050}

Alternative Form

β = 0.24 \dot{5} 74 \dot{2}

Simplify the expression