Solve 25y^2-98y-872=0

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

y_{1} = \frac{49 - 3 2689}{25}, y_{2} = \frac{49 + 3 2689}{25}

Alternative Form

y_{1} \approx - 4.262668, y_{2} \approx 8.182668

Evaluate

25 y^{2} - 98 y - 872 = 0

Substitute a= 25,b= - 98 and c= - 872 into the quadratic formula y = \frac{- b \pm b ^{2} - 4 a c}{2 a}

y = \frac{98 \pm ( - 98 ) ^{2} - 4 \times 25 ( - 872 )}{2 \times 25}

Simplify the expression

y = \frac{98 \pm ( - 98 ) ^{2} - 4 \times 25 ( - 872 )}{50}

Simplify the expression

More Steps

y = \frac{98 \pm 96804}{50}

Simplify the radical expression

More Steps

y = \frac{98 \pm 6 2689}{50}

Separate the equation into 2 possible cases

y = \frac{98 + 6 2689}{50} y = \frac{98 - 6 2689}{50}

Simplify the expression

More Steps

y = \frac{49 + 3 2689}{25} y = \frac{98 - 6 2689}{50}

Simplify the expression

More Steps

y = \frac{49 + 3 2689}{25} y = \frac{49 - 3 2689}{25}

Solution

y_{1} = \frac{49 - 3 2689}{25}, y_{2} = \frac{49 + 3 2689}{25}

Alternative Form

y_{1} \approx - 4.262668, y_{2} \approx 8.182668

Show Solution