Question
Solve the equation
c=5
Evaluate
27=3c−3(6−2c)
Swap the sides of the equation
3c−3(6−2c)=27
Move the expression to the left side
3c−3(6−2c)−27=0
Calculate
More Steps

Evaluate
3c−3(6−2c)−27
Expand the expression
More Steps

Calculate
−3(6−2c)
Apply the distributive property
−3×6−(−3×2c)
Multiply the numbers
−18−(−3×2c)
Multiply the numbers
−18−(−6c)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−18+6c
3c−18+6c−27
Add the terms
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Evaluate
3c+6c
Collect like terms by calculating the sum or difference of their coefficients
(3+6)c
Add the numbers
9c
9c−18−27
Subtract the numbers
9c−45
9c−45=0
Move the constant to the right-hand side and change its sign
9c=0+45
Removing 0 doesn't change the value,so remove it from the expression
9c=45
Divide both sides
99c=945
Divide the numbers
c=945
Solution
More Steps

Evaluate
945
Reduce the numbers
15
Calculate
5
c=5
Show Solution
