Solve 2h^2+o^2=2h^2o

Question

Solve the equation

Solve for h

Solve for o

h = \frac{∣ o ∣ \times - 2 + 2 o}{2 ∣ 1 - o ∣} h = - \frac{∣ o ∣ \times - 2 + 2 o}{2 ∣ 1 - o ∣}

Evaluate

2 h^{2} + o^{2} = 2 h^{2} o

Rewrite the expression

2 h^{2} + o^{2} = 2 o h^{2}

Move the expression to the left side

2 h^{2} + o^{2} - 2 o h^{2} = 0

Collect like terms by calculating the sum or difference of their coefficients

(2 - 2 o) h^{2} + o^{2} = 0

Move the constant to the right side

(2 - 2 o) h^{2} = - o^{2}

Divide both sides

\frac{( 2 - 2 o ) h ^{2}}{2 - 2 o} = \frac{- o ^{2}}{2 - 2 o}

Divide the numbers

h^{2} = \frac{- o ^{2}}{2 - 2 o}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

h^{2} = - \frac{o ^{2}}{2 - 2 o}

Take the root of both sides of the equation and remember to use both positive and negative roots

h = \pm - \frac{o ^{2}}{2 - 2 o}

Simplify the expression

More Steps

h = \pm \frac{∣ o ∣ \times - 2 + 2 o}{2 ∣ 1 - o ∣}

Solution

h = \frac{∣ o ∣ \times - 2 + 2 o}{2 ∣ 1 - o ∣} h = - \frac{∣ o ∣ \times - 2 + 2 o}{2 ∣ 1 - o ∣}

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