Question
Solve the equation
a=0
Evaluate
2k−2(k−1)a−k+1+(k−2)a=k+1−(k−1)a
Cancel equal terms on both sides of the expression
2k−2(k−1)a−k+(k−2)a=k−(k−1)a
Simplify
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Evaluate
2k−2(k−1)a−k+(k−2)a
Multiply the terms
2k−2a(k−1)−k+(k−2)a
Multiply the terms
2k−2a(k−1)−k+a(k−2)
Subtract the terms
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Evaluate
2k−k
Collect like terms by calculating the sum or difference of their coefficients
(2−1)k
Subtract the numbers
k
k−2a(k−1)+a(k−2)
Add the terms
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Evaluate
−2a(k−1)+a(k−2)
Rewrite the expression
−2(k−1)a+(k−2)a
Factor the expression
(−2(k−1)+k−2)a
Add the terms
−ka
k−ka
k−ka=k−(k−1)a
Multiply the terms
k−ka=k+a(−k+1)
Rewrite the expression
k−ka=k+(−k+1)a
Cancel equal terms on both sides of the expression
−ka=(−k+1)a
Add or subtract both sides
−ka−(−k+1)a=0
Subtract the terms
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Evaluate
−ka−(−k+1)a
Collect like terms by calculating the sum or difference of their coefficients
(−k−(−k+1))a
Subtract the terms
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Evaluate
−k−(−k+1)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−k+k−1
Since two opposites add up to 0,remove them form the expression
−1
−a
−a=0
Solution
a=0
Show Solution
