Solve 2k^2+3k-1=0

Evaluate

2 k^{2} + 3 k - 1 = 0

Substitute a= 2,b= 3 and c= - 1 into the quadratic formula k = \frac{- b \pm b ^{2} - 4 a c}{2 a}

k = \frac{- 3 \pm 3 ^{2} - 4 \times 2 ( - 1 )}{2 \times 2}

Simplify the expression

k = \frac{- 3 \pm 3 ^{2} - 4 \times 2 ( - 1 )}{4}

Simplify the expression

More Steps

k = \frac{- 3 \pm 17}{4}

Separate the equation into 2 possible cases

k = \frac{- 3 + 17}{4} k = \frac{- 3 - 17}{4}

Use \frac{- a}{b} = \frac{a}{- b} = - \frac{a}{b} to rewrite the fraction

k = \frac{- 3 + 17}{4} k = - \frac{3 + 17}{4}

Solution

k_{1} = - \frac{3 + 17}{4}, k_{2} = \frac{- 3 + 17}{4}

Alternative Form

k_{1} \approx - 1.780776, k_{2} \approx 0.280776

Solve the quadratic equation