Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
k1=0,k2=31
Alternative Form
k1=0,k2=0.3˙
Evaluate
2k2−6k3=0
Factor the expression
2k2(1−3k)=0
Divide both sides
k2(1−3k)=0
Separate the equation into 2 possible cases
k2=01−3k=0
The only way a power can be 0 is when the base equals 0
k=01−3k=0
Solve the equation
More Steps
Evaluate
1−3k=0
Move the constant to the right-hand side and change its sign
−3k=0−1
Removing 0 doesn't change the value,so remove it from the expression
−3k=−1
Change the signs on both sides of the equation
3k=1
Divide both sides
33k=31
Divide the numbers
k=31
k=0k=31
Solution
k1=0,k2=31
Alternative Form
k1=0,k2=0.3˙
Show Solution
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