Solve 2k^3-k^2-2k 1

Simplify the expression

2 k^{3} - k^{2} - 2 k

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k (2 k^{2} - k - 2)

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k_{1} = \frac{1 - 17}{4}, k_{2} = 0, k_{3} = \frac{1 + 17}{4}

Alternative Form

k_{1} \approx - 0.780776, k_{2} = 0, k_{3} \approx 1.280776

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