Question
Factor the expression
(n+3)(2n−3)
Evaluate
2n2+3n−9
Rewrite the expression
2n2+(−3+6)n−9
Calculate
2n2−3n+6n−9
Rewrite the expression
n×2n−n×3+3×2n−3×3
Factor out n from the expression
n(2n−3)+3×2n−3×3
Factor out 3 from the expression
n(2n−3)+3(2n−3)
Solution
(n+3)(2n−3)
Show Solution

Find the roots
n1=−3,n2=23
Alternative Form
n1=−3,n2=1.5
Evaluate
2n2+3n−9
To find the roots of the expression,set the expression equal to 0
2n2+3n−9=0
Factor the expression
More Steps

Evaluate
2n2+3n−9
Rewrite the expression
2n2+(−3+6)n−9
Calculate
2n2−3n+6n−9
Rewrite the expression
n×2n−n×3+3×2n−3×3
Factor out n from the expression
n(2n−3)+3×2n−3×3
Factor out 3 from the expression
n(2n−3)+3(2n−3)
Factor out 2n−3 from the expression
(n+3)(2n−3)
(n+3)(2n−3)=0
When the product of factors equals 0,at least one factor is 0
n+3=02n−3=0
Solve the equation for n
More Steps

Evaluate
n+3=0
Move the constant to the right-hand side and change its sign
n=0−3
Removing 0 doesn't change the value,so remove it from the expression
n=−3
n=−32n−3=0
Solve the equation for n
More Steps

Evaluate
2n−3=0
Move the constant to the right-hand side and change its sign
2n=0+3
Removing 0 doesn't change the value,so remove it from the expression
2n=3
Divide both sides
22n=23
Divide the numbers
n=23
n=−3n=23
Solution
n1=−3,n2=23
Alternative Form
n1=−3,n2=1.5
Show Solution
