Question
Factor the expression
(n−6)(2n+7)
Evaluate
2n2−5n−42
Rewrite the expression
2n2+(7−12)n−42
Calculate
2n2+7n−12n−42
Rewrite the expression
n×2n+n×7−6×2n−6×7
Factor out n from the expression
n(2n+7)−6×2n−6×7
Factor out −6 from the expression
n(2n+7)−6(2n+7)
Solution
(n−6)(2n+7)
Show Solution

Find the roots
n1=−27,n2=6
Alternative Form
n1=−3.5,n2=6
Evaluate
2n2−5n−42
To find the roots of the expression,set the expression equal to 0
2n2−5n−42=0
Factor the expression
More Steps

Evaluate
2n2−5n−42
Rewrite the expression
2n2+(7−12)n−42
Calculate
2n2+7n−12n−42
Rewrite the expression
n×2n+n×7−6×2n−6×7
Factor out n from the expression
n(2n+7)−6×2n−6×7
Factor out −6 from the expression
n(2n+7)−6(2n+7)
Factor out 2n+7 from the expression
(n−6)(2n+7)
(n−6)(2n+7)=0
When the product of factors equals 0,at least one factor is 0
n−6=02n+7=0
Solve the equation for n
More Steps

Evaluate
n−6=0
Move the constant to the right-hand side and change its sign
n=0+6
Removing 0 doesn't change the value,so remove it from the expression
n=6
n=62n+7=0
Solve the equation for n
More Steps

Evaluate
2n+7=0
Move the constant to the right-hand side and change its sign
2n=0−7
Removing 0 doesn't change the value,so remove it from the expression
2n=−7
Divide both sides
22n=2−7
Divide the numbers
n=2−7
Use b−a=−ba=−ba to rewrite the fraction
n=−27
n=6n=−27
Solution
n1=−27,n2=6
Alternative Form
n1=−3.5,n2=6
Show Solution
