Solve 2n^2-7n-3=0

Evaluate

2 n^{2} - 7 n - 3 = 0

Substitute a= 2,b= - 7 and c= - 3 into the quadratic formula n = \frac{- b \pm b ^{2} - 4 a c}{2 a}

n = \frac{7 \pm ( - 7 ) ^{2} - 4 \times 2 ( - 3 )}{2 \times 2}

Simplify the expression

n = \frac{7 \pm ( - 7 ) ^{2} - 4 \times 2 ( - 3 )}{4}

Simplify the expression

More Steps

n = \frac{7 \pm 73}{4}

Separate the equation into 2 possible cases

n = \frac{7 + 73}{4} n = \frac{7 - 73}{4}

Solution

n_{1} = \frac{7 - 73}{4}, n_{2} = \frac{7 + 73}{4}

Alternative Form

n_{1} \approx - 0.386001, n_{2} \approx 3.886001

Solve the quadratic equation