Question
Solve the equation
Solve for x
Solve for y
x=2y4
Evaluate
2x−y4=0
Move the expression to the right-hand side and change its sign
2x=0+y4
Add the terms
2x=y4
Divide both sides
22x=2y4
Solution
x=2y4
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Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
2x−y4=0
To test if the graph of 2x−y4=0 is symmetry with respect to the origin,substitute -x for x and -y for y
2(−x)−(−y)4=0
Evaluate
More Steps

Evaluate
2(−x)−(−y)4
Multiply the numbers
−2x−(−y)4
Rewrite the expression
−2x−y4
−2x−y4=0
Solution
Not symmetry with respect to the origin
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Rewrite the equation
r=0r=32cos(θ)csc(θ)×csc(θ)
Evaluate
2x−y4=0
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
2cos(θ)×r−(sin(θ)×r)4=0
Factor the expression
−sin4(θ)×r4+2cos(θ)×r=0
Factor the expression
r(−sin4(θ)×r3+2cos(θ))=0
When the product of factors equals 0,at least one factor is 0
r=0−sin4(θ)×r3+2cos(θ)=0
Solution
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Factor the expression
−sin4(θ)×r3+2cos(θ)=0
Subtract the terms
−sin4(θ)×r3+2cos(θ)−2cos(θ)=0−2cos(θ)
Evaluate
−sin4(θ)×r3=−2cos(θ)
Divide the terms
r3=sin4(θ)2cos(θ)
Simplify the expression
r3=2cos(θ)csc4(θ)
Simplify the expression
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Evaluate
32cos(θ)csc4(θ)
Rewrite the exponent as a sum
32cos(θ)csc3+1(θ)
Use am+n=am×an to expand the expression
32cos(θ)csc3(θ)csc(θ)
Rewrite the expression
3csc3(θ)×2cos(θ)csc(θ)
Calculate
csc(θ)×32cos(θ)csc(θ)
Calculate
32cos(θ)csc(θ)×csc(θ)
r=32cos(θ)csc(θ)×csc(θ)
r=0r=32cos(θ)csc(θ)×csc(θ)
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Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=2y31
Calculate
2x−y4=0
Take the derivative of both sides
dxd(2x−y4)=dxd(0)
Calculate the derivative
More Steps

Evaluate
dxd(2x−y4)
Use differentiation rules
dxd(2x)+dxd(−y4)
Evaluate the derivative
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Evaluate
dxd(2x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
2×dxd(x)
Use dxdxn=nxn−1 to find derivative
2×1
Any expression multiplied by 1 remains the same
2
2+dxd(−y4)
Evaluate the derivative
More Steps

Evaluate
dxd(−y4)
Use differentiation rules
dyd(−y4)×dxdy
Evaluate the derivative
−4y3dxdy
2−4y3dxdy
2−4y3dxdy=dxd(0)
Calculate the derivative
2−4y3dxdy=0
Move the constant to the right-hand side and change its sign
−4y3dxdy=0−2
Removing 0 doesn't change the value,so remove it from the expression
−4y3dxdy=−2
Divide both sides
−4y3−4y3dxdy=−4y3−2
Divide the numbers
dxdy=−4y3−2
Solution
dxdy=2y31
Show Solution

Find the second derivative
Find the second derivative with respect to x
Find the second derivative with respect to y
dx2d2y=−4y73
Calculate
2x−y4=0
Take the derivative of both sides
dxd(2x−y4)=dxd(0)
Calculate the derivative
More Steps

Evaluate
dxd(2x−y4)
Use differentiation rules
dxd(2x)+dxd(−y4)
Evaluate the derivative
More Steps

Evaluate
dxd(2x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
2×dxd(x)
Use dxdxn=nxn−1 to find derivative
2×1
Any expression multiplied by 1 remains the same
2
2+dxd(−y4)
Evaluate the derivative
More Steps

Evaluate
dxd(−y4)
Use differentiation rules
dyd(−y4)×dxdy
Evaluate the derivative
−4y3dxdy
2−4y3dxdy
2−4y3dxdy=dxd(0)
Calculate the derivative
2−4y3dxdy=0
Move the constant to the right-hand side and change its sign
−4y3dxdy=0−2
Removing 0 doesn't change the value,so remove it from the expression
−4y3dxdy=−2
Divide both sides
−4y3−4y3dxdy=−4y3−2
Divide the numbers
dxdy=−4y3−2
Cancel out the common factor −2
dxdy=2y31
Take the derivative of both sides
dxd(dxdy)=dxd(2y31)
Calculate the derivative
dx2d2y=dxd(2y31)
Use differentiation rules
dx2d2y=21×dxd(y31)
Rewrite the expression in exponential form
dx2d2y=21×dxd(y−3)
Calculate the derivative
More Steps

Evaluate
dxd(y−3)
Use differentiation rules
dyd(y−3)×dxdy
Use dxdxn=nxn−1 to find derivative
−3y−4dxdy
dx2d2y=21(−3y−4dxdy)
Rewrite the expression
dx2d2y=21(−y43dxdy)
Calculate
dx2d2y=−2y43dxdy
Use equation dxdy=2y31 to substitute
dx2d2y=−2y43×2y31
Solution
More Steps

Calculate
−2y43×2y31
Multiply the terms
−2y42y33
Divide the terms
More Steps

Evaluate
2y42y33
Multiply by the reciprocal
2y33×2y41
Multiply the terms
2y3×2y43
Multiply the terms
4y73
−4y73
dx2d2y=−4y73
Show Solution
