Question
Solve the equation
x=27
Alternative Form
x=3.5
Evaluate
2x+25−(5×xx)−1=x
Find the domain
2x+25−(5×xx)−1=x,x=0
Simplify
More Steps

Evaluate
2x+25−(5×xx)−1
Divide the terms
2x+25−(5×1)−1
Any expression multiplied by 1 remains the same
2x+25−5−1
Subtract the numbers
2x+25−6
Subtract the numbers
More Steps

Evaluate
25−6
Reduce fractions to a common denominator
25−26×2
Write all numerators above the common denominator
25−6×2
Multiply the numbers
25−12
Subtract the numbers
2−7
Use b−a=−ba=−ba to rewrite the fraction
−27
2x−27
2x−27=x
Move the variable to the left side
2x−27−x=0
Subtract the terms
More Steps

Evaluate
2x−x
Collect like terms by calculating the sum or difference of their coefficients
(2−1)x
Subtract the numbers
x
x−27=0
Move the constant to the right side
x=0+27
Removing 0 doesn't change the value,so remove it from the expression
x=27
Check if the solution is in the defined range
x=27,x=0
Solution
x=27
Alternative Form
x=3.5
Show Solution
