Solve 2x^(2)-15x-36=0

Evaluate

2 x^{2} - 15 x - 36 = 0

Substitute a= 2,b= - 15 and c= - 36 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 2 ( - 36 )}{2 \times 2}

Simplify the expression

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 2 ( - 36 )}{4}

Simplify the expression

More Steps

x = \frac{15 \pm 513}{4}

Simplify the radical expression

More Steps

x = \frac{15 \pm 3 57}{4}

Separate the equation into 2 possible cases

x = \frac{15 + 3 57}{4} x = \frac{15 - 3 57}{4}

Solution

x_{1} = \frac{15 - 3 57}{4}, x_{2} = \frac{15 + 3 57}{4}

Alternative Form

x_{1} \approx - 1.912376, x_{2} \approx 9.412376

Solve the quadratic equation