Solve 2x^(2)-4x-3

Evaluate

2 x^{2} - 4 x - 3

To find the roots of the expression,set the expression equal to 0

2 x^{2} - 4 x - 3 = 0

Substitute a= 2,b= - 4 and c= - 3 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{4 \pm ( - 4 ) ^{2} - 4 \times 2 ( - 3 )}{2 \times 2}

Simplify the expression

x = \frac{4 \pm ( - 4 ) ^{2} - 4 \times 2 ( - 3 )}{4}

Simplify the expression

More Steps

x = \frac{4 \pm 40}{4}

Simplify the radical expression

More Steps

x = \frac{4 \pm 2 10}{4}

Separate the equation into 2 possible cases

x = \frac{4 + 2 10}{4} x = \frac{4 - 2 10}{4}

Simplify the expression

More Steps

x = \frac{2 + 10}{2} x = \frac{4 - 2 10}{4}

Simplify the expression

More Steps

x = \frac{2 + 10}{2} x = \frac{2 - 10}{2}

Solution

x_{1} = \frac{2 - 10}{2}, x_{2} = \frac{2 + 10}{2}

Alternative Form

x_{1} \approx - 0.581139, x_{2} \approx 2.581139

Find the roots