Question
Factor the expression
(x+3)(2x+1)
Evaluate
2x2+7x+3
Rewrite the expression
2x2+(1+6)x+3
Calculate
2x2+x+6x+3
Rewrite the expression
x×2x+x+3×2x+3
Factor out x from the expression
x(2x+1)+3×2x+3
Factor out 3 from the expression
x(2x+1)+3(2x+1)
Solution
(x+3)(2x+1)
Show Solution

Find the roots
x1=−3,x2=−21
Alternative Form
x1=−3,x2=−0.5
Evaluate
2x2+7x+3
To find the roots of the expression,set the expression equal to 0
2x2+7x+3=0
Factor the expression
More Steps

Evaluate
2x2+7x+3
Rewrite the expression
2x2+(1+6)x+3
Calculate
2x2+x+6x+3
Rewrite the expression
x×2x+x+3×2x+3
Factor out x from the expression
x(2x+1)+3×2x+3
Factor out 3 from the expression
x(2x+1)+3(2x+1)
Factor out 2x+1 from the expression
(x+3)(2x+1)
(x+3)(2x+1)=0
When the product of factors equals 0,at least one factor is 0
x+3=02x+1=0
Solve the equation for x
More Steps

Evaluate
x+3=0
Move the constant to the right-hand side and change its sign
x=0−3
Removing 0 doesn't change the value,so remove it from the expression
x=−3
x=−32x+1=0
Solve the equation for x
More Steps

Evaluate
2x+1=0
Move the constant to the right-hand side and change its sign
2x=0−1
Removing 0 doesn't change the value,so remove it from the expression
2x=−1
Divide both sides
22x=2−1
Divide the numbers
x=2−1
Use b−a=−ba=−ba to rewrite the fraction
x=−21
x=−3x=−21
Solution
x1=−3,x2=−21
Alternative Form
x1=−3,x2=−0.5
Show Solution
