Solve 2x^2-12x-7=0

Evaluate

2 x^{2} - 12 x - 7 = 0

Substitute a= 2,b= - 12 and c= - 7 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{12 \pm ( - 12 ) ^{2} - 4 \times 2 ( - 7 )}{2 \times 2}

Simplify the expression

x = \frac{12 \pm ( - 12 ) ^{2} - 4 \times 2 ( - 7 )}{4}

Simplify the expression

More Steps

x = \frac{12 \pm 200}{4}

Simplify the radical expression

More Steps

x = \frac{12 \pm 10 2}{4}

Separate the equation into 2 possible cases

x = \frac{12 + 10 2}{4} x = \frac{12 - 10 2}{4}

Simplify the expression

More Steps

x = \frac{6 + 5 2}{2} x = \frac{12 - 10 2}{4}

Simplify the expression

More Steps

x = \frac{6 + 5 2}{2} x = \frac{6 - 5 2}{2}

Solution

x_{1} = \frac{6 - 5 2}{2}, x_{2} = \frac{6 + 5 2}{2}

Alternative Form

x_{1} \approx - 0.535534, x_{2} \approx 6.535534

Solve the quadratic equation