Solve 2x^2-3x-7=0

Evaluate

2 x^{2} - 3 x - 7 = 0

Substitute a= 2,b= - 3 and c= - 7 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 2 ( - 7 )}{2 \times 2}

Simplify the expression

x = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 2 ( - 7 )}{4}

Simplify the expression

More Steps

x = \frac{3 \pm 65}{4}

Separate the equation into 2 possible cases

x = \frac{3 + 65}{4} x = \frac{3 - 65}{4}

Solution

x_{1} = \frac{3 - 65}{4}, x_{2} = \frac{3 + 65}{4}

Alternative Form

x_{1} \approx - 1.265564, x_{2} \approx 2.765564

Solve the quadratic equation