Question Solve the quadratic equation Solve by factoring Solve using the quadratic formula Solve by completing the square Load more x1=−23,x2=5Alternative Form x1=−1.5,x2=5 Evaluate 2x2−7x=15Move the expression to the left side 2x2−7x−15=0Factor the expression More Steps Evaluate 2x2−7x−15Rewrite the expression 2x2+(3−10)x−15Calculate 2x2+3x−10x−15Rewrite the expression x×2x+x×3−5×2x−5×3Factor out x from the expression x(2x+3)−5×2x−5×3Factor out −5 from the expression x(2x+3)−5(2x+3)Factor out 2x+3 from the expression (x−5)(2x+3) (x−5)(2x+3)=0When the product of factors equals 0,at least one factor is 0 x−5=02x+3=0Solve the equation for x More Steps Evaluate x−5=0Move the constant to the right-hand side and change its sign x=0+5Removing 0 doesn't change the value,so remove it from the expression x=5 x=52x+3=0Solve the equation for x More Steps Evaluate 2x+3=0Move the constant to the right-hand side and change its sign 2x=0−3Removing 0 doesn't change the value,so remove it from the expression 2x=−3Divide both sides 22x=2−3Divide the numbers x=2−3Use b−a=−ba=−ba to rewrite the fraction x=−23 x=5x=−23Solution x1=−23,x2=5Alternative Form x1=−1.5,x2=5 Show Solution Graph