Question Solve the quadratic equation Solve by factoring Solve using the quadratic formula Solve by completing the square Load more x1=−25,x2=3Alternative Form x1=−2.5,x2=3 Evaluate 2x2−x−15=0Factor the expression More Steps Evaluate 2x2−x−15Rewrite the expression 2x2+(5−6)x−15Calculate 2x2+5x−6x−15Rewrite the expression x×2x+x×5−3×2x−3×5Factor out x from the expression x(2x+5)−3×2x−3×5Factor out −3 from the expression x(2x+5)−3(2x+5)Factor out 2x+5 from the expression (x−3)(2x+5) (x−3)(2x+5)=0When the product of factors equals 0,at least one factor is 0 x−3=02x+5=0Solve the equation for x More Steps Evaluate x−3=0Move the constant to the right-hand side and change its sign x=0+3Removing 0 doesn't change the value,so remove it from the expression x=3 x=32x+5=0Solve the equation for x More Steps Evaluate 2x+5=0Move the constant to the right-hand side and change its sign 2x=0−5Removing 0 doesn't change the value,so remove it from the expression 2x=−5Divide both sides 22x=2−5Divide the numbers x=2−5Use b−a=−ba=−ba to rewrite the fraction x=−25 x=3x=−25Solution x1=−25,x2=3Alternative Form x1=−2.5,x2=3 Show Solution Graph