Solve 2x^2-x-5=0 - ScanMath

Evaluate

2 x^{2} - x - 5 = 0

Substitute a= 2,b= - 1 and c= - 5 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{1 \pm ( - 1 ) ^{2} - 4 \times 2 ( - 5 )}{2 \times 2}

Simplify the expression

x = \frac{1 \pm ( - 1 ) ^{2} - 4 \times 2 ( - 5 )}{4}

Simplify the expression

More Steps

x = \frac{1 \pm 41}{4}

Separate the equation into 2 possible cases

x = \frac{1 + 41}{4} x = \frac{1 - 41}{4}

Solution

x_{1} = \frac{1 - 41}{4}, x_{2} = \frac{1 + 41}{4}

Alternative Form

x_{1} \approx - 1.350781, x_{2} \approx 1.850781

Solve the quadratic equation