Solve 2x^21=5x^48

Evaluate

2 x^{2} \times 1 = 5 x^{4} \times 8

Multiply the terms

2 x^{2} = 5 x^{4} \times 8

Multiply the terms

2 x^{2} = 40 x^{4}

Add or subtract both sides

2 x^{2} - 40 x^{4} = 0

Factor the expression

2 x^{2} (1 - 20 x^{2}) = 0

Divide both sides

x^{2} (1 - 20 x^{2}) = 0

Separate the equation into 2 possible cases

x^{2} = 0 1 - 20 x^{2} = 0

The only way a power can be 0 is when the base equals 0

x = 0 1 - 20 x^{2} = 0

Solve the equation

More Steps

x = 0 x = \frac{5}{10} x = - \frac{5}{10}

Solution

x_{1} = - \frac{5}{10}, x_{2} = 0, x_{3} = \frac{5}{10}

Alternative Form

x_{1} \approx - 0.223607, x_{2} = 0, x_{3} \approx 0.223607

Solve the equation