Solve 2x^3-5x 7 - ScanMath

Question

Simplify the expression

2 x^{3} - 35 x

Evaluate

2 x^{3} - 5 x \times 7

Solution

2 x^{3} - 35 x

Show Solution

x (2 x^{2} - 35)

Evaluate

2 x^{3} - 5 x \times 7

Multiply the terms

2 x^{3} - 35 x

Rewrite the expression

x \times 2 x^{2} - x \times 35

Solution

x (2 x^{2} - 35)

Show Solution

x_{1} = - \frac{70}{2}, x_{2} = 0, x_{3} = \frac{70}{2}

Alternative Form

x_{1} \approx - 4.1833, x_{2} = 0, x_{3} \approx 4.1833

Evaluate

2 x^{3} - 5 x \times 7

To find the roots of the expression,set the expression equal to 0

2 x^{3} - 5 x \times 7 = 0

Multiply the terms

2 x^{3} - 35 x = 0

Factor the expression

x (2 x^{2} - 35) = 0

Separate the equation into 2 possible cases

x = 0 2 x^{2} - 35 = 0

Solve the equation

More Steps

Evaluate

2 x^{2} - 35 = 0

Move the constant to the right-hand side and change its sign

2 x^{2} = 0 + 35

Removing 0 doesn't change the value,so remove it from the expression

2 x^{2} = 35

Divide both sides

\frac{2 x ^{2}}{2} = \frac{35}{2}

Divide the numbers

x^{2} = \frac{35}{2}

Take the root of both sides of the equation and remember to use both positive and negative roots

x = \pm \frac{35}{2}

Simplify the expression

More Steps

Evaluate

\frac{35}{2}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{35}{2}

Multiply by the Conjugate

\frac{35 \times 2}{2 \times 2}

Multiply the numbers

\frac{70}{2 \times 2}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{70}{2}

x = \pm \frac{70}{2}

Separate the equation into 2 possible cases

x = \frac{70}{2} x = - \frac{70}{2}

x = 0 x = \frac{70}{2} x = - \frac{70}{2}

Solution

x_{1} = - \frac{70}{2}, x_{2} = 0, x_{3} = \frac{70}{2}

Alternative Form

x_{1} \approx - 4.1833, x_{2} = 0, x_{3} \approx 4.1833

Show Solution