Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
2(x−2)(x+1)2
Evaluate
2x3−6x−4
Rewrite the expression
2x3−2×3x−2×2
Factor out 2 from the expression
2(x3−3x−2)
Factor the expression
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Evaluate
x3−3x−2
Calculate
x3+2x2+x−2x2−4x−2
Rewrite the expression
x×x2+x×2x+x−2x2−2×2x−2
Factor out x from the expression
x(x2+2x+1)−2x2−2×2x−2
Factor out −2 from the expression
x(x2+2x+1)−2(x2+2x+1)
Factor out x2+2x+1 from the expression
(x−2)(x2+2x+1)
2(x−2)(x2+2x+1)
Solution
2(x−2)(x+1)2
Show Solution
Find the roots
x1=−1,x2=2
Evaluate
2x3−6x−4
To find the roots of the expression,set the expression equal to 0
2x3−6x−4=0
Factor the expression
2(x−2)(x+1)2=0
Divide both sides
(x−2)(x+1)2=0
Separate the equation into 2 possible cases
x−2=0(x+1)2=0
Solve the equation
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Evaluate
x−2=0
Move the constant to the right side
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x=2(x+1)2=0
Solve the equation
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Evaluate
(x+1)2=0
The only way a power can be 0 is when the base equals 0
x+1=0
Move the constant to the right-hand side and change its sign
x=0−1
Removing 0 doesn't change the value,so remove it from the expression
x=−1
x=2x=−1
Solution
x1=−1,x2=2
Show Solution