Solve 2x^5y = 16 - ScanMath

Solve the equation

Solve for x

Solve for y

x = \frac{5 8 y ^{4}}{y}

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Testing for symmetry about the origin

Testing for symmetry about the x-axis

Testing for symmetry about the y-axis

Symmetry with respect to the origin

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r = 6 8 sec^{5} (θ) csc (θ) r = - 6 8 sec^{5} (θ) csc (θ)

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Find the derivative with respect to x

Find the derivative with respect to y

\frac{d y}{d x} = - \frac{5 y}{x}

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Find the second derivative with respect to x

Find the second derivative with respect to y

\frac{d ^{2} y}{d x ^{2}} = \frac{30 y}{x ^{2}}

Calculate

2 x^{5} y = 16

Take the derivative of both sides

\frac{d}{d x} (2 x^{5} y) = \frac{d}{d x} (16)

Calculate the derivative

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10 x^{4} y + 2 x^{5} \frac{d y}{d x} = \frac{d}{d x} (16)

Calculate the derivative

10 x^{4} y + 2 x^{5} \frac{d y}{d x} = 0

Move the expression to the right-hand side and change its sign

2 x^{5} \frac{d y}{d x} = 0 - 10 x^{4} y

Removing 0 doesn't change the value,so remove it from the expression

2 x^{5} \frac{d y}{d x} = - 10 x^{4} y

Divide both sides

\frac{2 x ^{5} \frac{d y}{d x}}{2 x ^{5}} = \frac{- 10 x ^{4} y}{2 x ^{5}}

Divide the numbers

\frac{d y}{d x} = \frac{- 10 x ^{4} y}{2 x ^{5}}

Divide the numbers

More Steps

\frac{d y}{d x} = - \frac{5 y}{x}

Take the derivative of both sides

\frac{d}{d x} (\frac{d y}{d x}) = \frac{d}{d x} (- \frac{5 y}{x})

Calculate the derivative

\frac{d ^{2} y}{d x ^{2}} = \frac{d}{d x} (- \frac{5 y}{x})

Use differentiation rules

\frac{d ^{2} y}{d x ^{2}} = - \frac{\frac{d}{d x} ( 5 y ) \times x - 5 y \times \frac{d}{d x} ( x )}{x ^{2}}

Calculate the derivative

More Steps

\frac{d ^{2} y}{d x ^{2}} = - \frac{5 \frac{d y}{d x} \times x - 5 y \times \frac{d}{d x} ( x )}{x ^{2}}

Use \frac{d}{d x} x^{n} = n x^{n - 1} to find derivative

\frac{d ^{2} y}{d x ^{2}} = - \frac{5 \frac{d y}{d x} \times x - 5 y \times 1}{x ^{2}}

Use the commutative property to reorder the terms

\frac{d ^{2} y}{d x ^{2}} = - \frac{5 x \frac{d y}{d x} - 5 y \times 1}{x ^{2}}

Any expression multiplied by 1 remains the same

\frac{d ^{2} y}{d x ^{2}} = - \frac{5 x \frac{d y}{d x} - 5 y}{x ^{2}}

Use equation \frac{d y}{d x} = - \frac{5 y}{x} to substitute

\frac{d ^{2} y}{d x ^{2}} = - \frac{5 x ( - \frac{5 y}{x} ) - 5 y}{x ^{2}}

Solution

More Steps

\frac{d ^{2} y}{d x ^{2}} = \frac{30 y}{x ^{2}}

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