Algebra
Calculus
Trigonometry
Matrix
Question
Find the roots
x1≈−1.265148,x2≈1.265148
Evaluate
2x6−2x2−5
To find the roots of the expression,set the expression equal to 0
2x6−2x2−5=0
Solve the equation using substitution t=x2
2t3−2t−5=0
Calculate
t≈1.600599
Substitute back
x2≈1.600599
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±1.600599
Simplify the expression
x=±1.265148
Separate the equation into 2 possible cases
x≈1.265148x≈−1.265148
Solution
x1≈−1.265148,x2≈1.265148
Show Solution
