Question
Factor the expression
(y−2)(2y+1)
Evaluate
2y2−3y−2
Rewrite the expression
2y2+(1−4)y−2
Calculate
2y2+y−4y−2
Rewrite the expression
y×2y+y−2×2y−2
Factor out y from the expression
y(2y+1)−2×2y−2
Factor out −2 from the expression
y(2y+1)−2(2y+1)
Solution
(y−2)(2y+1)
Show Solution

Find the roots
y1=−21,y2=2
Alternative Form
y1=−0.5,y2=2
Evaluate
2y2−3y−2
To find the roots of the expression,set the expression equal to 0
2y2−3y−2=0
Factor the expression
More Steps

Evaluate
2y2−3y−2
Rewrite the expression
2y2+(1−4)y−2
Calculate
2y2+y−4y−2
Rewrite the expression
y×2y+y−2×2y−2
Factor out y from the expression
y(2y+1)−2×2y−2
Factor out −2 from the expression
y(2y+1)−2(2y+1)
Factor out 2y+1 from the expression
(y−2)(2y+1)
(y−2)(2y+1)=0
When the product of factors equals 0,at least one factor is 0
y−2=02y+1=0
Solve the equation for y
More Steps

Evaluate
y−2=0
Move the constant to the right-hand side and change its sign
y=0+2
Removing 0 doesn't change the value,so remove it from the expression
y=2
y=22y+1=0
Solve the equation for y
More Steps

Evaluate
2y+1=0
Move the constant to the right-hand side and change its sign
2y=0−1
Removing 0 doesn't change the value,so remove it from the expression
2y=−1
Divide both sides
22y=2−1
Divide the numbers
y=2−1
Use b−a=−ba=−ba to rewrite the fraction
y=−21
y=2y=−21
Solution
y1=−21,y2=2
Alternative Form
y1=−0.5,y2=2
Show Solution
