Solve 2y^2 - 5y - 2

Evaluate

2 y^{2} - 5 y - 2

To find the roots of the expression,set the expression equal to 0

2 y^{2} - 5 y - 2 = 0

Substitute a= 2,b= - 5 and c= - 2 into the quadratic formula y = \frac{- b \pm b ^{2} - 4 a c}{2 a}

y = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 2 ( - 2 )}{2 \times 2}

Simplify the expression

y = \frac{5 \pm ( - 5 ) ^{2} - 4 \times 2 ( - 2 )}{4}

Simplify the expression

More Steps

y = \frac{5 \pm 41}{4}

Separate the equation into 2 possible cases

y = \frac{5 + 41}{4} y = \frac{5 - 41}{4}

Solution

y_{1} = \frac{5 - 41}{4}, y_{2} = \frac{5 + 41}{4}

Alternative Form

y_{1} \approx - 0.350781, y_{2} \approx 2.850781

Find the roots