Question
Factor the expression
(y+2)(2y+5)
Evaluate
2y2+9y+10
Rewrite the expression
2y2+(5+4)y+10
Calculate
2y2+5y+4y+10
Rewrite the expression
y×2y+y×5+2×2y+2×5
Factor out y from the expression
y(2y+5)+2×2y+2×5
Factor out 2 from the expression
y(2y+5)+2(2y+5)
Solution
(y+2)(2y+5)
Show Solution

Find the roots
y1=−25,y2=−2
Alternative Form
y1=−2.5,y2=−2
Evaluate
2y2+9y+10
To find the roots of the expression,set the expression equal to 0
2y2+9y+10=0
Factor the expression
More Steps

Evaluate
2y2+9y+10
Rewrite the expression
2y2+(5+4)y+10
Calculate
2y2+5y+4y+10
Rewrite the expression
y×2y+y×5+2×2y+2×5
Factor out y from the expression
y(2y+5)+2×2y+2×5
Factor out 2 from the expression
y(2y+5)+2(2y+5)
Factor out 2y+5 from the expression
(y+2)(2y+5)
(y+2)(2y+5)=0
When the product of factors equals 0,at least one factor is 0
y+2=02y+5=0
Solve the equation for y
More Steps

Evaluate
y+2=0
Move the constant to the right-hand side and change its sign
y=0−2
Removing 0 doesn't change the value,so remove it from the expression
y=−2
y=−22y+5=0
Solve the equation for y
More Steps

Evaluate
2y+5=0
Move the constant to the right-hand side and change its sign
2y=0−5
Removing 0 doesn't change the value,so remove it from the expression
2y=−5
Divide both sides
22y=2−5
Divide the numbers
y=2−5
Use b−a=−ba=−ba to rewrite the fraction
y=−25
y=−2y=−25
Solution
y1=−25,y2=−2
Alternative Form
y1=−2.5,y2=−2
Show Solution
