Solve 2y^2-3y-1=0

Evaluate

2 y^{2} - 3 y - 1 = 0

Substitute a= 2,b= - 3 and c= - 1 into the quadratic formula y = \frac{- b \pm b ^{2} - 4 a c}{2 a}

y = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 2 ( - 1 )}{2 \times 2}

Simplify the expression

y = \frac{3 \pm ( - 3 ) ^{2} - 4 \times 2 ( - 1 )}{4}

Simplify the expression

More Steps

y = \frac{3 \pm 17}{4}

Separate the equation into 2 possible cases

y = \frac{3 + 17}{4} y = \frac{3 - 17}{4}

Solution

y_{1} = \frac{3 - 17}{4}, y_{2} = \frac{3 + 17}{4}

Alternative Form

y_{1} \approx - 0.280776, y_{2} \approx 1.780776

Solve the quadratic equation