Question Solve the quadratic equation Solve by factoring Solve using the quadratic formula Solve by completing the square Load more y1=−25,y2=3Alternative Form y1=−2.5,y2=3 Evaluate 2y2−y−15=0Factor the expression More Steps Evaluate 2y2−y−15Rewrite the expression 2y2+(5−6)y−15Calculate 2y2+5y−6y−15Rewrite the expression y×2y+y×5−3×2y−3×5Factor out y from the expression y(2y+5)−3×2y−3×5Factor out −3 from the expression y(2y+5)−3(2y+5)Factor out 2y+5 from the expression (y−3)(2y+5) (y−3)(2y+5)=0When the product of factors equals 0,at least one factor is 0 y−3=02y+5=0Solve the equation for y More Steps Evaluate y−3=0Move the constant to the right-hand side and change its sign y=0+3Removing 0 doesn't change the value,so remove it from the expression y=3 y=32y+5=0Solve the equation for y More Steps Evaluate 2y+5=0Move the constant to the right-hand side and change its sign 2y=0−5Removing 0 doesn't change the value,so remove it from the expression 2y=−5Divide both sides 22y=2−5Divide the numbers y=2−5Use b−a=−ba=−ba to rewrite the fraction y=−25 y=3y=−25Solution y1=−25,y2=3Alternative Form y1=−2.5,y2=3 Show Solution Graph