Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
(y−1)(y+1)(2y+1)
Evaluate
2y3+y2−2y−1
Rewrite the expression
y2×2y+y2−2y−1
Factor out y2 from the expression
y2(2y+1)−2y−1
Factor out −1 from the expression
y2(2y+1)−(2y+1)
Factor out 2y+1 from the expression
(y2−1)(2y+1)
Solution
(y−1)(y+1)(2y+1)
Show Solution
Find the roots
y1=−1,y2=−21,y3=1
Alternative Form
y1=−1,y2=−0.5,y3=1
Evaluate
2y3+y2−2y−1
To find the roots of the expression,set the expression equal to 0
2y3+y2−2y−1=0
Factor the expression
(y−1)(y+1)(2y+1)=0
Separate the equation into 3 possible cases
y−1=0y+1=02y+1=0
Solve the equation
More Steps
Evaluate
y−1=0
Move the constant to the right-hand side and change its sign
y=0+1
Removing 0 doesn't change the value,so remove it from the expression
y=1
y=1y+1=02y+1=0
Solve the equation
More Steps
Evaluate
y+1=0
Move the constant to the right-hand side and change its sign
y=0−1
Removing 0 doesn't change the value,so remove it from the expression
y=−1
y=1y=−12y+1=0
Solve the equation
More Steps
Evaluate
2y+1=0
Move the constant to the right-hand side and change its sign
2y=0−1
Removing 0 doesn't change the value,so remove it from the expression
2y=−1
Divide both sides
22y=2−1
Divide the numbers
y=2−1
Use b−a=−ba=−ba to rewrite the fraction
y=−21
y=1y=−1y=−21
Solution
y1=−1,y2=−21,y3=1
Alternative Form
y1=−1,y2=−0.5,y3=1
Show Solution