Question
Function
Find the x-intercept/zero
Find the y-intercept
Find the slope
x=0
Evaluate
2y−3x=0
To find the x-intercept,set y=0
2×0−3x=0
Any expression multiplied by 0 equals 0
0−3x=0
Removing 0 doesn't change the value,so remove it from the expression
−3x=0
Change the signs on both sides of the equation
3x=0
Solution
x=0
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Solve the equation
Solve for x
Solve for y
x=32y
Evaluate
2y−3x=0
Move the expression to the right-hand side and change its sign
−3x=0−2y
Removing 0 doesn't change the value,so remove it from the expression
−3x=−2y
Change the signs on both sides of the equation
3x=2y
Divide both sides
33x=32y
Solution
x=32y
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Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Symmetry with respect to the origin
Evaluate
2y−3x=0
To test if the graph of 2y−3x=0 is symmetry with respect to the origin,substitute -x for x and -y for y
2(−y)−3(−x)=0
Evaluate
More Steps

Evaluate
2(−y)−3(−x)
Multiply the numbers
−2y−3(−x)
Multiply the numbers
−2y−(−3x)
Rewrite the expression
−2y+3x
−2y+3x=0
Solution
Symmetry with respect to the origin
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Rewrite the equation
Rewrite in polar form
Rewrite in standard form
Rewrite in slope-intercept form
r=0θ=arccot(32)+kπ,k∈Z
Evaluate
2y−3x=0
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
2sin(θ)×r−3cos(θ)×r=0
Factor the expression
(2sin(θ)−3cos(θ))r=0
Separate into possible cases
r=02sin(θ)−3cos(θ)=0
Solution
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Evaluate
2sin(θ)−3cos(θ)=0
Move the expression to the right side
−3cos(θ)=0−2sin(θ)
Subtract the terms
−3cos(θ)=−2sin(θ)
Divide both sides
sin(θ)−3cos(θ)=−2
Divide the terms
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Evaluate
sin(θ)−3cos(θ)
Use b−a=−ba=−ba to rewrite the fraction
−sin(θ)3cos(θ)
Rewrite the expression
−3sin−1(θ)cos(θ)
Rewrite the expression
−3cot(θ)
−3cot(θ)=−2
Multiply both sides of the equation by −31
−3cot(θ)(−31)=−2(−31)
Calculate
cot(θ)=−2(−31)
Calculate
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Evaluate
−2(−31)
Multiplying or dividing an even number of negative terms equals a positive
2×31
Multiply the numbers
32
cot(θ)=32
Use the inverse trigonometric function
θ=arccot(32)
Add the period of kπ,k∈Z to find all solutions
θ=arccot(32)+kπ,k∈Z
r=0θ=arccot(32)+kπ,k∈Z
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Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=23
Calculate
2y−3x=0
Take the derivative of both sides
dxd(2y−3x)=dxd(0)
Calculate the derivative
More Steps

Evaluate
dxd(2y−3x)
Use differentiation rules
dxd(2y)+dxd(−3x)
Evaluate the derivative
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Evaluate
dxd(2y)
Use differentiation rules
dyd(2y)×dxdy
Evaluate the derivative
2dxdy
2dxdy+dxd(−3x)
Evaluate the derivative
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Evaluate
dxd(−3x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
−3×dxd(x)
Use dxdxn=nxn−1 to find derivative
−3×1
Any expression multiplied by 1 remains the same
−3
2dxdy−3
2dxdy−3=dxd(0)
Calculate the derivative
2dxdy−3=0
Move the constant to the right-hand side and change its sign
2dxdy=0+3
Removing 0 doesn't change the value,so remove it from the expression
2dxdy=3
Divide both sides
22dxdy=23
Solution
dxdy=23
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Find the second derivative
Find the second derivative with respect to x
Find the second derivative with respect to y
dx2d2y=0
Calculate
2y−3x=0
Take the derivative of both sides
dxd(2y−3x)=dxd(0)
Calculate the derivative
More Steps

Evaluate
dxd(2y−3x)
Use differentiation rules
dxd(2y)+dxd(−3x)
Evaluate the derivative
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Evaluate
dxd(2y)
Use differentiation rules
dyd(2y)×dxdy
Evaluate the derivative
2dxdy
2dxdy+dxd(−3x)
Evaluate the derivative
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Evaluate
dxd(−3x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
−3×dxd(x)
Use dxdxn=nxn−1 to find derivative
−3×1
Any expression multiplied by 1 remains the same
−3
2dxdy−3
2dxdy−3=dxd(0)
Calculate the derivative
2dxdy−3=0
Move the constant to the right-hand side and change its sign
2dxdy=0+3
Removing 0 doesn't change the value,so remove it from the expression
2dxdy=3
Divide both sides
22dxdy=23
Divide the numbers
dxdy=23
Take the derivative of both sides
dxd(dxdy)=dxd(23)
Calculate the derivative
dx2d2y=dxd(23)
Solution
dx2d2y=0
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