Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
−32<I<0
Alternative Form
I∈(−32,0)
Evaluate
3I<I−I4
Move the expression to the left side
3I−(I−I4)<0
Subtract the terms
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Evaluate
3I−(I−I4)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
3I−I+I4
Subtract the terms
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Evaluate
3I−I
Collect like terms by calculating the sum or difference of their coefficients
(3−1)I
Subtract the numbers
2I
2I+I4
2I+I4<0
Rewrite the expression
2I+I4=0
Factor the expression
I(2+I3)=0
Separate the equation into 2 possible cases
I=02+I3=0
Solve the equation
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Evaluate
2+I3=0
Move the constant to the right-hand side and change its sign
I3=0−2
Removing 0 doesn't change the value,so remove it from the expression
I3=−2
Take the 3-th root on both sides of the equation
3I3=3−2
Calculate
I=3−2
An odd root of a negative radicand is always a negative
I=−32
I=0I=−32
Determine the test intervals using the critical values
I<−32−32<I<0I>0
Choose a value form each interval
I1=−2I2=−1I3=1
To determine if I<−32 is the solution to the inequality,test if the chosen value I=−2 satisfies the initial inequality
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Evaluate
3(−2)<−2−(−2)4
Multiply the numbers
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Evaluate
3(−2)
Multiplying or dividing an odd number of negative terms equals a negative
−3×2
Multiply the numbers
−6
−6<−2−(−2)4
Subtract the numbers
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Simplify
−2−(−2)4
Rewrite the expression
−2−24
Evaluate the power
−2−16
Subtract the numbers
−18
−6<−18
Check the inequality
false
I<−32 is not a solutionI2=−1I3=1
To determine if −32<I<0 is the solution to the inequality,test if the chosen value I=−1 satisfies the initial inequality
More Steps

Evaluate
3(−1)<−1−(−1)4
Simplify
−3<−1−(−1)4
Simplify
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Evaluate
−1−(−1)4
Evaluate the power
−1−1
Subtract the numbers
−2
−3<−2
Check the inequality
true
I<−32 is not a solution−32<I<0 is the solutionI3=1
To determine if I>0 is the solution to the inequality,test if the chosen value I=1 satisfies the initial inequality
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Evaluate
3×1<1−14
Any expression multiplied by 1 remains the same
3<1−14
Simplify
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Evaluate
1−14
1 raised to any power equals to 1
1−1
Subtract the terms
0
3<0
Check the inequality
false
I<−32 is not a solution−32<I<0 is the solutionI>0 is not a solution
Solution
−32<I<0
Alternative Form
I∈(−32,0)
Show Solution
