Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
83x5
Evaluate
x583
Multiply by the reciprocal
3×8x5
Solution
83x5
Show Solution
Find the excluded values
x=0
Evaluate
x583
To find the excluded values,set the denominators equal to 0
x5=0x58=0
The only way a power can be 0 is when the base equals 0
x=0x58=0
Solve the equations
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Evaluate
x58=0
Cross multiply
8=x5×0
Simplify the equation
8=0
The statement is false for any value of x
x∈∅
x=0x∈∅
Solution
x=0
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Find the roots
x∈∅
Evaluate
x583
To find the roots of the expression,set the expression equal to 0
x583=0
Find the domain
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Evaluate
{x5=0x58=0
The only way a power can not be 0 is when the base not equals 0
{x=0x58=0
Calculate
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Evaluate
x58=0
Multiply both sides
x58×x5=0×x5
Evaluate
8=0×x5
Multiply both sides
8=0
The statement is true for any value of x
x∈R
{x=0x∈R
Find the intersection
x=0
x583=0,x=0
Calculate
x583=0
Divide the terms
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Evaluate
x583
Multiply by the reciprocal
3×8x5
Multiply the terms
83x5
83x5=0
Simplify
3x5=0
Rewrite the expression
x5=0
The only way a power can be 0 is when the base equals 0
x=0
Check if the solution is in the defined range
x=0,x=0
Solution
x∈∅
Show Solution