Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,2)∪(5,+∞)
Evaluate
x−23<1
Find the domain
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Evaluate
x−2=0
Move the constant to the right side
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x−23<1,x=2
Move the expression to the left side
x−23−1<0
Subtract the terms
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Evaluate
x−23−1
Reduce fractions to a common denominator
x−23−x−2x−2
Write all numerators above the common denominator
x−23−(x−2)
Subtract the terms
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Evaluate
3−(x−2)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
3−x+2
Add the numbers
5−x
x−25−x
x−25−x<0
Set the numerator and denominator of x−25−x equal to 0 to find the values of x where sign changes may occur
5−x=0x−2=0
Calculate
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Evaluate
5−x=0
Move the constant to the right-hand side and change its sign
−x=0−5
Removing 0 doesn't change the value,so remove it from the expression
−x=−5
Change the signs on both sides of the equation
x=5
x=5x−2=0
Calculate
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Evaluate
x−2=0
Move the constant to the right-hand side and change its sign
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x=5x=2
Determine the test intervals using the critical values
x<22<x<5x>5
Choose a value form each interval
x1=1x2=4x3=6
To determine if x<2 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
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Evaluate
1−23<1
Simplify
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Evaluate
1−23
Subtract the numbers
−13
Divide the terms
−3
−3<1
Check the inequality
true
x<2 is the solutionx2=4x3=6
To determine if 2<x<5 is the solution to the inequality,test if the chosen value x=4 satisfies the initial inequality
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Evaluate
4−23<1
Subtract the numbers
23<1
Calculate
1.5<1
Check the inequality
false
x<2 is the solution2<x<5 is not a solutionx3=6
To determine if x>5 is the solution to the inequality,test if the chosen value x=6 satisfies the initial inequality
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Evaluate
6−23<1
Subtract the numbers
43<1
Calculate
0.75<1
Check the inequality
true
x<2 is the solution2<x<5 is not a solutionx>5 is the solution
The original inequality is a strict inequality,so does not include the critical value ,the final solution is x∈(−∞,2)∪(5,+∞)
x∈(−∞,2)∪(5,+∞)
Check if the solution is in the defined range
x∈(−∞,2)∪(5,+∞),x=2
Solution
x∈(−∞,2)∪(5,+∞)
Show Solution
