Solve 3(8x^2) =4(6x-10)

Question

Solve the equation(The real numbers system)

x \in / R

Alternative Form

No real solution

Show Solution

Solve using the quadratic formula in the complex numbers system

Solve by completing the square in the complex numbers system

Solve using the PQ formula in the complex numbers system

x_{1} = \frac{1}{2} - \frac{51}{6} i, x_{2} = \frac{1}{2} + \frac{51}{6} i

Alternative Form

x_{1} \approx 0.5 - 1.190238 i, x_{2} \approx 0.5 + 1.190238 i

Evaluate

3 \times 8 x^{2} = 4 (6 x - 10)

Multiply the numbers

24 x^{2} = 4 (6 x - 10)

Expand the expression

More Steps

24 x^{2} = 24 x - 40

Move the expression to the left side

24 x^{2} - 24 x + 40 = 0

Substitute a= 24,b= - 24 and c= 40 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{24 \pm ( - 24 ) ^{2} - 4 \times 24 \times 40}{2 \times 24}

Simplify the expression

x = \frac{24 \pm ( - 24 ) ^{2} - 4 \times 24 \times 40}{48}

Simplify the expression

More Steps

x = \frac{24 \pm - 3264}{48}

Simplify the radical expression

More Steps

x = \frac{24 \pm 8 51 \times i}{48}

Separate the equation into 2 possible cases

x = \frac{24 + 8 51 \times i}{48} x = \frac{24 - 8 51 \times i}{48}

Simplify the expression

More Steps

x = \frac{1}{2} + \frac{51}{6} i x = \frac{24 - 8 51 \times i}{48}

Simplify the expression

More Steps

x = \frac{1}{2} + \frac{51}{6} i x = \frac{1}{2} - \frac{51}{6} i

Solution

x_{1} = \frac{1}{2} - \frac{51}{6} i, x_{2} = \frac{1}{2} + \frac{51}{6} i

Alternative Form

x_{1} \approx 0.5 - 1.190238 i, x_{2} \approx 0.5 + 1.190238 i

Show Solution