Solve 3(x-5)/62x/4 =7

Evaluate

(3 \times \frac{x - 5}{62}) \times \frac{x}{4} = 7

Remove the parentheses

3 \times \frac{x - 5}{62} \times \frac{x}{4} = 7

Multiply the terms

More Steps

\frac{3 ( x - 5 ) x}{248} = 7

Rewrite the expression

\frac{3}{248} x^{2} - \frac{15}{248} x = 7

Move the expression to the left side

\frac{3}{248} x^{2} - \frac{15}{248} x - 7 = 0

Multiply both sides

248 (\frac{3}{248} x^{2} - \frac{15}{248} x - 7) = 248 \times 0

Calculate

3 x^{2} - 15 x - 1736 = 0

Substitute a= 3,b= - 15 and c= - 1736 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 3 ( - 1736 )}{2 \times 3}

Simplify the expression

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 3 ( - 1736 )}{6}

Simplify the expression

More Steps

x = \frac{15 \pm 21057}{6}

Separate the equation into 2 possible cases

x = \frac{15 + 21057}{6} x = \frac{15 - 21057}{6}

Solution

x_{1} = \frac{15 - 21057}{6}, x_{2} = \frac{15 + 21057}{6}

Alternative Form

x_{1} \approx - 21.68505, x_{2} \approx 26.68505

Solve the quadratic equation