Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
Solve for x
x∈(−∞,−35)∪(1,+∞)
Evaluate
3x2+2x>5
Move the expression to the left side
3x2+2x−5>0
Rewrite the expression
3x2+2x−5=0
Factor the expression
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Evaluate
3x2+2x−5
Rewrite the expression
3x2+(5−3)x−5
Calculate
3x2+5x−3x−5
Rewrite the expression
x×3x+x×5−3x−5
Factor out x from the expression
x(3x+5)−3x−5
Factor out −1 from the expression
x(3x+5)−(3x+5)
Factor out 3x+5 from the expression
(x−1)(3x+5)
(x−1)(3x+5)=0
When the product of factors equals 0,at least one factor is 0
x−1=03x+5=0
Solve the equation for x
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Evaluate
x−1=0
Move the constant to the right-hand side and change its sign
x=0+1
Removing 0 doesn't change the value,so remove it from the expression
x=1
x=13x+5=0
Solve the equation for x
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Evaluate
3x+5=0
Move the constant to the right-hand side and change its sign
3x=0−5
Removing 0 doesn't change the value,so remove it from the expression
3x=−5
Divide both sides
33x=3−5
Divide the numbers
x=3−5
Use b−a=−ba=−ba to rewrite the fraction
x=−35
x=1x=−35
Determine the test intervals using the critical values
x<−35−35<x<1x>1
Choose a value form each interval
x1=−3x2=−1x3=2
To determine if x<−35 is the solution to the inequality,test if the chosen value x=−3 satisfies the initial inequality
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Evaluate
3(−3)2+2(−3)>5
Simplify
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Evaluate
3(−3)2+2(−3)
Multiply the terms
33+2(−3)
Multiply the numbers
33−6
Evaluate the power
27−6
Subtract the numbers
21
21>5
Check the inequality
true
x<−35 is the solutionx2=−1x3=2
To determine if −35<x<1 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
3(−1)2+2(−1)>5
Simplify
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Evaluate
3(−1)2+2(−1)
Evaluate the power
3×1+2(−1)
Any expression multiplied by 1 remains the same
3+2(−1)
Simplify
3−2
Subtract the numbers
1
1>5
Check the inequality
false
x<−35 is the solution−35<x<1 is not a solutionx3=2
To determine if x>1 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
More Steps

Evaluate
3×22+2×2>5
Simplify
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Evaluate
3×22+2×2
Multiply the terms
12+2×2
Multiply the numbers
12+4
Add the numbers
16
16>5
Check the inequality
true
x<−35 is the solution−35<x<1 is not a solutionx>1 is the solution
Solution
x∈(−∞,−35)∪(1,+∞)
Show Solution
