Algebra
Calculus
Trigonometry
Matrix
Question
Solve the equation
b=−1
Evaluate
3−2(b−2)=2−7b
Move the expression to the left side
3−2(b−2)−(2−7b)=0
Subtract the terms
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Evaluate
3−2(b−2)−(2−7b)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
3−2(b−2)−2+7b
Subtract the numbers
1−2(b−2)+7b
1−2(b−2)+7b=0
Calculate the sum or difference
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Evaluate
1−2(b−2)+7b
Expand the expression
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Calculate
−2(b−2)
Apply the distributive property
−2b−(−2×2)
Multiply the numbers
−2b−(−4)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−2b+4
1−2b+4+7b
Add the numbers
5−2b+7b
Add the terms
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Evaluate
−2b+7b
Collect like terms by calculating the sum or difference of their coefficients
(−2+7)b
Add the numbers
5b
5+5b
5+5b=0
Move the constant to the right-hand side and change its sign
5b=0−5
Removing 0 doesn't change the value,so remove it from the expression
5b=−5
Divide both sides
55b=5−5
Divide the numbers
b=5−5
Solution
More Steps
Evaluate
5−5
Reduce the numbers
1−1
Calculate
−1
b=−1
Show Solution
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