Solve 39y^3(50y^2-98)/26y^2(5y+7) - ScanMath

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Type your math problem... 39y^3(50y^2-98)/26y^2(5y+7)

Question

Simplify the expression

375 y^{8} + 525 y^{7} - 735 y^{6} - 1029 y^{5}

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Factor the expression

3 y^{5} (5 y - 7) (5 y + 7)^{2}

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Find the roots

y_{1} = - \frac{7}{5}, y_{2} = 0, y_{3} = \frac{7}{5}

Alternative Form

y_{1} = - 1.4, y_{2} = 0, y_{3} = 1.4

Evaluate

39 y^{3} \times \frac{50 y ^{2} - 98}{26} \times y^{2} (5 y + 7)

To find the roots of the expression,set the expression equal to 0

39 y^{3} \times \frac{50 y ^{2} - 98}{26} \times y^{2} (5 y + 7) = 0

Divide the terms

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39 y^{3} \times \frac{25 y ^{2} - 49}{13} \times y^{2} (5 y + 7) = 0

Multiply

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3 y^{5} (25 y^{2} - 49) (5 y + 7) = 0

Elimination the left coefficient

y^{5} (25 y^{2} - 49) (5 y + 7) = 0

Separate the equation into 3 possible cases

y^{5} = 0 25 y^{2} - 49 = 0 5 y + 7 = 0

The only way a power can be 0 is when the base equals 0

y = 0 25 y^{2} - 49 = 0 5 y + 7 = 0

Solve the equation

More Steps

y = 0 y = \frac{7}{5} y = - \frac{7}{5} 5 y + 7 = 0

Solve the equation

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y = 0 y = \frac{7}{5} y = - \frac{7}{5} y = - \frac{7}{5}

Find the union

y = 0 y = \frac{7}{5} y = - \frac{7}{5}

Solution

y_{1} = - \frac{7}{5}, y_{2} = 0, y_{3} = \frac{7}{5}

Alternative Form

y_{1} = - 1.4, y_{2} = 0, y_{3} = 1.4

Show Solution