Question Solve the system of equations Solve using the substitution method Solve using the elimination method (a,b)∈∅Alternative Form No solution Evaluate {3ab=6−2ab6−2ab=−3Solve the equation for a More Steps Evaluate 3ab=6−2abEvaluate 3ba=6−2baMove the variable to the left side 3ba+2ba=6Add the terms More Steps Evaluate 3ba+2baCollect like terms by calculating the sum or difference of their coefficients (3+2)baAdd the numbers 5ba 5ba=6Divide both sides 5b5ba=5b6Divide the numbers a=5b6 {a=5b66−2ab=−3Substitute the given value of a into the equation 6−2ab=−3 6−2×5b6×b=−3Simplify More Steps Evaluate 6−2×5b6×bMultiply the terms More Steps Multiply the terms 2×5b6×bMultiply the terms 5b12×bCancel out the common factor b 512×1Multiply the terms 512 6−512Reduce fractions to a common denominator 56×5−512Write all numerators above the common denominator 56×5−12Multiply the numbers 530−12Subtract the numbers 518 518=−3Calculate {a∈∅b∈∅Solution (a,b)∈∅Alternative Form No solution Show Solution